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CSEC>> Chemistry

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Structure and bonding
Francine Taylor-Campbell, Contributor

Students of Vauxhall Comprehensive High School perform a skit during World Wetlands Day 2006 celebrations at the University of the West Indies marine lab at Port Royal on Thursday, February 2. - Andrew Smith/Photography Editor

SYLLABUS REQUIREMENTS

  • Explain the formation of ionic and covalent bonds.

  • Predict the likelihood of an atom forming an ionic or covalent bond based on atomic structure.

  • Write formulae to represent ions and molecules.

  • Explain metallic bonding.

Now, let us examine the following questions.

1. Which solid does not contain covalent bonds?

A. Copper
B. Diamond
C. Graphite
D. Ice

2. The elements X and Y form the compound X2Y. What is the correct electron arrangement of the atoms X and Y?

Atom XAtom Y
A. 2 : 7 2
B. 2 : 22 : 7
C. 2 : 22 : 6
D. 2 : 12 : 6

3. In which set do the three particles each have the same total number of electrons?

A. Cl- Br- I-
B. F- Ne Na+
C. K+ Ca2+ Br-
D. Li+ Na+ K+

4. What is the formula of iron (III) nitrate?

A. Fe (NO3)3
B. Fe2 (NO3)3
C. Fe2NO3
D. Fe3 (NO3)2

5. Elements X and Y react to form an ionic compound of formula XY. What could be the proton (atomic) numbers of X and Y?

 XY
A.38
B.68
C.8 16
D.1216

ANSWERS AND COMMENTS


1. A. Covalent bonds are formed between non-metals. Diamond and graphite are made up of carbon which is a non-metal, while ice (frozen H2O) consists of bonds between hydrogen and oxygen which are also non-metals. This leaves copper which exhibits metallic bonding.

2. D. From the formula Y would form the ion Y2- and 2 X+ ions would combine to produce X2Y. This means that Y is in Group 6 needing 2 electrons to be stable and X is in group I since it has lost one electron to be stable. Thus the electron arrangement for X is 2:1 and for Y is 2:6.

3. B. Fluorine gains an electron to have the electron arrangement 2:8, the neon atom is 2:8 and sodium loses an electron to have a 2:8 arrangement. This totals 10 electrons for all three particles.

4. A. Iron (III) has a charge of +3 and the nitrate ion (NO3) - has a charge of -1. These ions must combine in a way so that their charges cancel out to zero. Thus it will take 3 nitrate ions (3 x -1) = -3 to cancel out the +3 charge on one iron. -3 + 3 = 0.

5. D. X has the arrangement 2:8:2 and Y has the arrangement 2:8:6. Thus as X loses 2 electrons to be stable, they are gained by Y which needs 2 to be stable. It requires one X to bond with one Y. The formula is XY.

It is important to review the notes on this topic so that you can answer structured and essay type questions as well.

 
 
 
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