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Avogadro's
law and molar volume
Francine
Taylor-Campbell, Contributor
REVIEW
OF FACTS
Avogadro's
Law states that equal volumes of all
gases measured at the same temperature
and pressure contain equal numbers
of molecules.
The
temperatures and pressures usually
used are standard temperature and
pressure (STP), which is 00C and 1
atmosphere pressure and room temperature
(RTP) which is 200C and 1 atmosphere
pressure.
1
dm3 of any gas at STP contains the
same number of molecules as 1 dm3
of any other gas at STP.
22.4
dm3 of any gas contains L molecules
(6.0 * 1023) at STP. This is one mole
of the gas and is called the molar
volume.
At
RTP the molar volume is 24 dm3.
CALCULATIONS
ON MOLAR VOLUME
1(a)
What is the volume of 8g of oxygen
at (i) RTP (ii) STP
1
mole of oxygen (O2) = 2 * 16 = 32g
32g
= 24dm3 at RTP and 22.4 dm3 at STP
Thus
8g = 24/4 dm3 at RTP and 22.4/4 dm3
at STP
Volume
of 8g of O2 at RTP = 6 dm3 and at
STP = 5.6 dm3
(b)
Calculate the mass of 4.8 dm3 of (i)
N2 (ii) CO2 at RTP.
(i)
1 mole of N2 = 28g
24
dm3 at RTP = 28g
4.8
dm3 = (28 * 4.8)/24 = 5.6g
(ii)
4.8 dm3 of CO2 at RTP = (44 * 4.8)/24
= 8.8g
(c)
Calculate the volumes of the following
at RTP
(i)
35.5g of Cl2
(ii)
1.7g NH3
(iii)
4g H2
d)
Calculate the mass of 2.8 dm3 of each
of the following gases at STP
(i)
NO2
(ii)
HBr
(iii)
C2H6.
2.
This question is concerned with the
mole and its application.
Define
the following:
Avogadro's
law
The
mole
The
relative molar mass
(6
mks)
Determine
(i)
the number of moles of carbon in 18g
of carbon (Relative atomic mass: C
= 12)
(ii)
the number of atoms in 18g of carbon
(iii)
the number of molecules in 4.9g of
sulphuric acid (RMM of sulphuric acid
= 98)
(3
mks)
(c)
At room temperature and atmospheric
pressure (r.t.p.), 1.6g of methane
occupy a volume of 2.4dm3. Calculate
the relative molar mass
of methane. (ONE mole of any gas at
r.t.p. has a volume of 24 dm3)
(2
mks)
ANSWERS
2.
(a) (i) Avogadro's law states that
equal volumes of gases measured at
the same temperature and pressure
contain equal number of molecules.
(ii)
The mole is the amount of substance
that contains Avogadro's number of
particles, that is 6.0*1023 particles.
(iii)
The relative molar mass is the mass
of one mole of a substance compared
with the mass of one atom of carbon-12.
(b)
(i) Number of moles of carbon == 1.5
mol (1 mol of carbon has a mass of
12g. Therefore, # mol in 18g == 18g/12
gmol-1 = 1.5 mol)
(ii)
18 g of carbon == 1.5 mol
Now
1 mol has 6.0*1023 atoms, thus 1.5
mol has 1.5 x 6.0*1023
atoms
== 9 * 1023 atoms.
(iii)
# mol in 4.9g of sulphuric acid (H2SO4)
= 4.9/98 == 0.05 mol
Number
of molecules of H2SO4 == 0.05 x 6.0*1023
= 3*1022 molecules.
(c)
1 mole CH4 has volume of 24dm3 at
r.t.p.
Volume
of gas = 2.4 dm3 thus # mol = 2.4/24
= 0.1 mol CH4
mol
CH4 has a mass of 1.6g
Molar
mass or mass of 1 mol = 1.6/0.1 ==
16g/mol
Francine
Taylor-Campbell is an independent
contributor. Send questions and comments
to kerry-ann.hepburn@gleanerjm.com
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