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CSEC>> Mathematics

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Solving quadratic equations
Clement Radcliffe, Contributor

Let me hope that you had a merry Christmas and are poised for a prosperous New Year. This I expect will be with respect to your efforts in mathematics.

I will now proceed to present some reminders of how to solve quadratic equations.

* Solve 2x² - 6x - 1 = 0

From the equation, a = 2, b = - 6 and c = - 1.

Answer: x =3.16 and - 0.16

* Solve 2x² - 3x - 4 = 2 - 4x

First simplify the equation:

2x² - 3x + 4x - 4 - 2 = 0

2x² + x - 6 = 0 Factorising

(2x - 3)(x + 2) = 0

2x - 3 = 0, that is x = 3
2

And x + 2 = 0, that is x = -2.

Answer: x = 3/2 and -2

Quadratic equations may also be solved using the method of completion of squares.

COMPLETION OF SQUARES

Given the equation x² + bx + c = 0, the aim is to convert the equation to the form (x + d)² = k, where d and k are constants. You are therefore required to CONVERT the left hand side to a PERECT SQUARE of form (x + d)². Given the form (x + d)² = k, then x is found by determining the square root of both sides.

(x + d)² = k
(x + d) = ± k
x = - d ± k

As was the case previously, the ± (plus or minus) will enable you to find the two values of x.

Example:

Solve: x² + 6x - 5 = 0, using completion of squares.

Given x² + 6x - 5 = 0, the first critical step is to transfer the constant to the right hand side (RHS):

x² + 6x = 5

This is followed by making the left hand side a perfect square. This is based on the following equation:

(x + a) ² = x² + 2ax + a² .

Given x² + 2ax, then a², the square of half the coefficient of x, must be added to complete the square.

Given x² + 6x, then (6/2)² or 3², the square of half the coefficient of x is required to make the left hand side a perfect square.

x² + 6x + 9 = 5 + 9 = 14

3² or 9 is added to both sides of the equation so that the value of x remains unchanged.

x² + 6x + 9 = 14. (Factorising the LHS)

(x + 3)² = 14. Find the square root of both sides

x + 3 = ± 14 = ± 3.74
x + 3 = 3.74, that is x = 0.74
OR x + 3 = -3.74, that is x = - 6.74

Answer x = 0.74 or - 6.74

I am sure you won't mind us practising the following together.

Examples:

(1) Express x² - 8x = 1 in the form (x + a)² = b.

As ( 8/2 )² = 16, then 16 must be added to both sides to make the LHS a perfect square.

x² - 8x + 16 = 1 + 16 Factorising the LHS

(x - 4)² = 17.

You may expand to check your answers.

(2) Find the values to be added to the L.H.S. to make it a perfect square.

(a) x² - 12x = 1
(b) y² + 9x = 4

Your answers should be 36 and 81 respectively. If this is not so, then please review the method.
4

Now let us solve the above examples together.

(a) Solve x² - 8x = 1

If x² - 8x = 1

Completing the squares:

x² - 8x + 16 = 1 + 16
(x - 4)² = 17

x - 4 = ± 17
x = 4 ± 4.12
x = 8.12 and -.12

(b) Solve x² - 12x = 1
Since x² - 12x = 1

Completing the squares:

x² - 12x + 36 = 1 + 36
(x - 6)² = 37

x - 6 = ± 37

x = 6 ± 6.08
x = 12.08 and -.08

Set out below is your homework.

Solve the following equations, using the completion of squares method.

(1) x² + 9x - 4 = 0
(2) x² + 8x - 9 = 0
(3) x² = 7x + 5

* Clement Radcliffe is principal of Glenmuir High School in Clarendon.

 
 
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