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CSEC>> Mathematics

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Directed numbers
Clement Radcliffe, Contributor

Students of William Knibb Memorial High School, Trelawny, take notes during day two of The Gleaner's Youthlink CSEC seminar in Montego Bay, in April. - Tashieka Mair/Freelance Photographer
As we continue our review of Directed Numbers, you are invited to look at the answers to the problems given for Homework last week.Evaluate the following:

1) -4 x -3 = 12 -21 ÷ 3 = -7

2) -18 -10 + 6 = -22 5a x -4b = -20ab

3) 12/25 x 5/9 ÷ 5/18 = 12/25 x 5/9 x 18/5
= 24/25

4) 11/12 + 5/6 -2/3

(Please note that the LCM of 12, 6 and 3 is 12)

= (1 x 11) + (2 x 5) - (4 x 2) = 13
12
12

If the above posed no difficulty, then you are ready to consider exam-type questions.

Application of the Four Arithmetic Operations to Vulgar Fractions

In applying the four basic operations to vulgar fractions, students are required to observe the correct law with respect to the order of operation as follows:

B - Brackets
O - Of (Multiply)
M - Multiply
D - Divide
A - Add
S - Subtract

BOMDAS identifies the order in which the operations should be carried out and must always be obeyed.

Let's practise the use of BOMDAS.

(a) Practice 1

Calculate the value of: 1 1/2 + 5 x 2 ÷ 1 2/3

We do the multiplication first:

1 1/2+ 10 ÷ 1 2/3

We then do the division:

1 1/2 + [10 x 3/5]

= 11/2 + 6
= 7 1/2

(b) Practice 2

8 x (2 1/3 + 1/2) We first do the brackets (although we are required to add):

ie. (2 1/3 + 1/2 ) = 7/3 + 1/2 . Using the L.C.M. of 2 and 3, that is 6, we get

14 + 3 = 17
6
6

To complete the problem, we now multiply:

8 x 17/6 = 683 = 22 2/3

(c) Practice 3

Calculate the value of:

4 1/3 - 1 5/6 
1 3/7 x 2 2/3 

The line represents brackets and so the numerator may be evaluated first.

4 1/3 - 1 5/6 = 13/3 - 11/6

26-11 = 15
6
6

Evaluating the denominator:

13/7 x 2 2/3 = 10/7 x 8/3 = 80/21

Dividing

= 15/6 ÷ 80/21 = 15/6 x 21/80 = 21/32

Points to note

  • In solving a problem such as Practice 3, you may first evaluate either the numerator or the denominator.

  • Finding the L.C.M. CORRECTLY is a very important step in the solution.

  • As practice 3 requires the exact value, you are not allowed to express the fraction in decimal form. If this is done, then your answer would be different from 21/32 and you may be penalised.

  • Your working must always be clearly shown in logical sequence.

I close this week with the following:

1. Calculate the value of 2 1/3 - 1 1/2, expressing your answer as a fraction.

2. Evaluate: 16 x 5 ÷ 8 25 7 25

3 Simplify (2 1/3 ÷1 5/8) ÷ 1 1/3


4. Find the value of: 18.75 - (2.11)²

(No. 1 (a) (ii), CXC January 2006)


5. Find the value of:

2 1/4 x 4/5
3/5 - 1/2

(No. 1 (a) (i), CXC January 2006)

Finally, let me recommend that you keep all of these lessons together in a scrap book so that you can always refer to them. If you require previous copies you should be able to access these from the Gleaner Company.

Clement Radcliffe teaches at Glenmuir High School.

 
 
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