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CSEC>> Mathematics

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Practice Questions
Clement Radcliffe,
Contributor

Ashley Douilliard of St. Andrew High School for Girls entertains during the World YWCA Day 'Round the World breakfast', at 16 Beverly Drive, St. Andrew, on April 24, under the theme 'Honouring Women Leaders'. - Andrew Smith/ Photography Editor

As we continue our review of Directed Numbers, I will share with you the answers to the problems given for homework last week.

Evaluate the following:

(i) -5 x -3 = 15

(ii) -21 3 = -7

(iv) -8 -10 + 6 = -12

(v) 5a x -6b = -30ab

(vi) 12/25 + 5/9 5/18
12/25 x 5/9 5/18 = 12/25 x 5/9 x 18/5 = 24/25

If the above posed no difficulty, then you are ready to consider exam type questions.

Application of the Foour Arithmetic Operations to Vulgar Fractions

In applying the four basic operations to vulgar fractions, students are required to observe the correct law with respect to the order of operation as follows:

B - Brackets
O - Of (Multiply)
M - Multiply
D - Divide
A - Add
S - Subtract

BOMDAS identifies the order in which the operations should be carried out and must always be obeyed.

Let's practice the use of BOMDAS

(a) Practice 1

Calculate the value of: 1 1/2 + 5 x 2 1 2/3

Convert to Common Factor
= 3/2 + 5 x 2 5/3

We do the multiplication first:

3/2 + 10 5/3

We then do the division:
3/2 + [10 x 3/5]
= 3/2 + 6
= 7 1/2

(b) Practice 2

4 x (2 1/3 + 1/2)
We first do the brackets (although we are required to add):
ie. (2 1/3 + 1/2) = 7/3 + 1/2
Using the L.C.M. of 2 and 3, that is 6, we get
=
(2 x 7) + (3 x 1)
6
=
14 + 3
=17
6
 6

To complete the problem, we now multiply:
4 x 17/6 = 68/6 = 11 2/3

(c) Practice 3

Calculate the value of: 6 1/3 - 1 5/6
 1 1/2 x 2 2/3

The line represents brackets and so the numerator may be evaluated first.

6 1/3 - 1 5/6 = 19/3 - 11/6
 = (2 x 19) - (1 x 11)
 
6
 
 = 38 - 11 = 27
 
6
6

Evaluating the denominator:

3/2 x 8/3 = 24/6

Dividing: = 27/6 24/6 = 27/6 x 6/24 = 9/8

Please to note

  • In solving a problem such as Practice 3, you may first evaluate either the numerator or the denominator.

  • Finding the L.C.M. CORRECTLY is a very important step in the solution.

  • As Practice 3 requires the exact value, you are not allowed to express the fraction in decimal form. If this is done, then your answer would be difficult from 9/8 and you may be penalized.

  • Your working must be always clearly shown in logical sequence.

Let us now work the following together:

Using a calculator, or otherwise, determine the exact value of
(3.7)² - (6.24 - 1.3).

Solution

(3.7)² - (6.24 - 1.3)
Using the recommended approach, we first evaluate the bracket.

(3.7)² = 13.69 and (6.24 - 1.3) = 4.80
= 13.69 - 4.80 = 8.89
Ans = 8.89

I close this week with the following:

1. Calculate the value of 4 1/2 x 2/3 - 1/4

2. Evaluate: 7/10 [2/5 + 4/15 x 3/5]

3. Simplify [2 1/3 - 1 5/8] 1 1/3

4. Find the value of: 18.75 - (2.11)² (No. 1 (a) (ii), CXC January 2006)

5. Find the value of: 2 1/4 x 4/5
(No. 1 (a) (i), CXC January 2006)
 3/5 - 1/2

Finally, let us urge you to keep all of these lessons together in a scrap book so that you can always refer to them. If you require previous copies you should be able to access these from the Gleaner Company.

Clement Radcliffe is the principal of Glenmuir High School in May Pen.

 
 
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