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Clement
Radcliffe, Contributor
This
week we will complete the review of
algebra by considering aspects of
graphs. Specifically, it is my intention
to elaborate on the solution of quadratic
equations using a graph.
REMINDERS
- A
quadratic equation is represented
graphically by a curve.
- A
curve should be drawn by free hand
sketch.
- The
x axis has the equation y = 0 and
the y axis has the equation x =
0.
- Given
the curve y = f(x) and the line
y = g(x), then the points of intersection
of both are represented by:
y
= f(x) = g(x)
...
f(x) = g(x)
If
f(x) = x2 - 3x + 2 and
g(x) = 2x - 1
then
at the point of intersection of the
curve and the line f(x) = g(x).
...
x2 - 3x + 2 = 2x - 1
...
x2 - 3x - 2x + 2 + 1 =
0
...
x2 - 5x + 3 = 0
The
x coordinates of the points of intersection
is, therefore, the solution of the
equation x2 - 3x + 2 =
2x - 1 OR x2 - 5x + 3 =
0.
EXAMPLE
Using
an appropriate scale, please plot
the curve y = 3x2 - 2x
- 1. Hence solve the equations:
a)
3x2 - 2x - 1 = 0
b)
3x2 - 2x - 1 = 2 - 2x
c)
3x2 - 3 = 0 or x2
- 1 = 0
SOLUTION
Given
the equation y = 3x2 -
2x - 1, we complete the table:
| x
|
-
2 |
-
1 |
0 |
1 |
2 |
3 |
| y |
15 |
4 |
-
1 |
0 |
7 |
20 |
Given
the curve y = 3x2 - 2x
- 1, then the curve may be used to
solve any equation as long as 3x2
- 2x - 1 is on one side of the equation.
To
solve the equation 3x2
- 3 ==0 then the equation must be
reorganised to the form with 3x2
- 2x - 1 on the left hand side.
a)
Given the curve y = 3x2
- 2x - 1, the solution of the equation
3x2 - 2x - 1 = 0 is the
x values of the points of intersection
of the curve y = 3x2 -
2x - 1 and the line y = 0 or the x
axis.
...
The solution is x = 1, - .33
b)
Given the curve y = 3x2
- 2x - 1, by plotting the line y =
2 - 2x, then the points of intersection
of the curve and the line will represent
the solution of the equation
3x2
- 2x - 1 = 2 - 2x.
From
the graph, the solution is x
= - 1, 1.
c)
Given the equation 3x2
- 3 = 0, if the curve y = 3x2
- 2x - 1 must be used, then
3x2
- 3 = 0 is reorganised as follows:
3x2
- 2x + 2x - 2 - 1 = 0.
...
3x2 - 2x - 1 + 2x -2 =
0
...
3x2 - 2x - 1 = 2 - 2x
...
The solution of the equation 3x2
- 3 = 0 or x2 - 1 = 0 is
the x coordinates of the points of
intersection of the curve y = 3x2
- 2x - 1 and the line y = 2 - 2x.
...
As in b), x = - 1, 1.
Let
us complete this lesson with the solution
to the following:
Given
the curve y = 2x2 - 3x
+ 1, find the equation of the line
which should be used to solve the
following equations:
(a)
2x2 - 4x - 2 = 0.
(b)
x2 + x - 1 = 0
Solution
Given
the curve y = 2x2 - 3x
+ 1, then the expression 2x2
- 3x + 1 must always be on the left
hand side.
(a)
2x2 - 4x - 2 = 0 is reorganised
as follows:
2x2
- 3x - x + 1 - 3 = 0
2x2
- 3x + 1 - x - 3 = 0
...
2x2 - 3x + 1 = x + 3
NB.
The line is y = x + 3.
(b)
x2 + x - 1 = 0. Reorganising
...
2x2 + 2x - 2 = 0
...
2x2 - 3x + 5x + 1 - 3 =
0
...
2x2 - 3x + 1 + 5x - 3 =
0
...
2x2 - 3x + 1 = 3 - 5x
...
The line is y = 3 - 5x
Let
us attempt another example.
Given
the curve y = 2x2 - x -
3, solve the equation 2x2
- 2x - 5 = 0.
By
reorganising the equation 2x2
- 2x - 5 = 0, it follows that:
2x2
-x -x - 3 -2 = 0
...
2x2 -x- 3 = x + 2
Then
the solution of 2x2 - 2x
- 5 = 0 is the x coordinates of the
points of intersection of the curve
y = 2x2 -x- 3 and the line
y = x + 2.
Please
continue to practise, using exercises
from your texts.
Enjoy
the rest of the week.
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From
left: Setu Monroe, Sanya Steen,
Noelle Yvette Hoskins, Professor
Gordon Shirley, Principal, Dawna
Candice Jones, Aieka Smith,
Tricishanna Racquel Henry and
Shawna-Kay McLarty at the University
of the West Indies' award of
the 60th Anniversary Mona Scholarships,
held in the Council Room, Mona
campus on Monday, December 22,
2008.
- Winston Sill/Freelance Photographer
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Clement
Radcliffe is the principal of Glenmuir
High School in May Pen.
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