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CSEC>> Mathematics

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Clement Radcliffe, Contributor

This week we will complete the review of algebra by considering aspects of graphs. Specifically, it is my intention to elaborate on the solution of quadratic equations using a graph.

REMINDERS

  • A quadratic equation is represented graphically by a curve.
  • A curve should be drawn by free hand sketch.
  • The x axis has the equation y = 0 and the y axis has the equation x = 0.
  • Given the curve y = f(x) and the line y = g(x), then the points of intersection of both are represented by:

y = f(x) = g(x)

... f(x) = g(x)

If f(x) = x2 - 3x + 2 and g(x) = 2x - 1

then at the point of intersection of the curve and the line f(x) = g(x).

... x2 - 3x + 2 = 2x - 1

... x2 - 3x - 2x + 2 + 1 = 0

... x2 - 5x + 3 = 0

The x coordinates of the points of intersection is, therefore, the solution of the equation x2 - 3x + 2 = 2x - 1 OR x2 - 5x + 3 = 0.

EXAMPLE

Using an appropriate scale, please plot the curve y = 3x2 - 2x - 1. Hence solve the equations:

a) 3x2 - 2x - 1 = 0

b) 3x2 - 2x - 1 = 2 - 2x

c) 3x2 - 3 = 0 or x2 - 1 = 0

SOLUTION

Given the equation y = 3x2 - 2x - 1, we complete the table:

x - 2 - 1 0 1 2 3
y 15 4 - 1 0 7 20

Given the curve y = 3x2 - 2x - 1, then the curve may be used to solve any equation as long as 3x2 - 2x - 1 is on one side of the equation.

To solve the equation 3x2 - 3 ==0 then the equation must be reorganised to the form with 3x2 - 2x - 1 on the left hand side.

a) Given the curve y = 3x2 - 2x - 1, the solution of the equation 3x2 - 2x - 1 = 0 is the x values of the points of intersection of the curve y = 3x2 - 2x - 1 and the line y = 0 or the x axis.

... The solution is x = 1, - .33

b) Given the curve y = 3x2 - 2x - 1, by plotting the line y = 2 - 2x, then the points of intersection of the curve and the line will represent the solution of the equation

3x2 - 2x - 1 = 2 - 2x.

From the graph, the solution is x = - 1, 1.

c) Given the equation 3x2 - 3 = 0, if the curve y = 3x2 - 2x - 1 must be used, then

3x2 - 3 = 0 is reorganised as follows:

3x2 - 2x + 2x - 2 - 1 = 0.

... 3x2 - 2x - 1 + 2x -2 = 0

... 3x2 - 2x - 1 = 2 - 2x

... The solution of the equation 3x2 - 3 = 0 or x2 - 1 = 0 is the x coordinates of the points of intersection of the curve y = 3x2 - 2x - 1 and the line y = 2 - 2x.

... As in b), x = - 1, 1.

Let us complete this lesson with the solution to the following:

Given the curve y = 2x2 - 3x + 1, find the equation of the line which should be used to solve the following equations:

(a) 2x2 - 4x - 2 = 0.

(b) x2 + x - 1 = 0

Solution

Given the curve y = 2x2 - 3x + 1, then the expression 2x2 - 3x + 1 must always be on the left hand side.

(a) 2x2 - 4x - 2 = 0 is reorganised as follows:

2x2 - 3x - x + 1 - 3 = 0

2x2 - 3x + 1 - x - 3 = 0

... 2x2 - 3x + 1 = x + 3

NB. The line is y = x + 3.

(b) x2 + x - 1 = 0. Reorganising

... 2x2 + 2x - 2 = 0

... 2x2 - 3x + 5x + 1 - 3 = 0

... 2x2 - 3x + 1 + 5x - 3 = 0

... 2x2 - 3x + 1 = 3 - 5x

... The line is y = 3 - 5x

Let us attempt another example.

Given the curve y = 2x2 - x - 3, solve the equation 2x2 - 2x - 5 = 0.

By reorganising the equation 2x2 - 2x - 5 = 0, it follows that:

2x2 -x -x - 3 -2 = 0

... 2x2 -x- 3 = x + 2

Then the solution of 2x2 - 2x - 5 = 0 is the x coordinates of the points of intersection of the curve y = 2x2 -x- 3 and the line y = x + 2.

Please continue to practise, using exercises from your texts.

Enjoy the rest of the week.

From left: Setu Monroe, Sanya Steen, Noelle Yvette Hoskins, Professor Gordon Shirley, Principal, Dawna Candice Jones, Aieka Smith, Tricishanna Racquel Henry and Shawna-Kay McLarty at the University of the West Indies' award of the 60th Anniversary Mona Scholarships, held in the Council Room, Mona campus on Monday, December 22, 2008.
- Winston Sill/Freelance Photographer

Clement Radcliffe is the principal of Glenmuir High School in May Pen.

 
 
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