yl:
ARTISTE
yl:
WESTERN LINK
yl:
FASHION & STYLE
yl:
DEAR COUNSELLOR
yl:
RELATIONSHIPS
yl:
TALKING HEADS
yl:
ON THE RISE
yl:
CELEBRITY QUIZ
yl:
TEEN TRENDS
yl:
TECHNO TEENS
yl:
SHORT STORY
yl:
ONLINE POLL
yl:
FEEDBACK
JOIN THE CLUB

Your Views on YL
If you've got an opinion, share it with the world on our
Message Boards

CSEC>> Mathematics

Click to go back to maths index
Click to go back cxc to archive

Completion of Squares
Clement Radcliffe,
Contributor

In this week's lesson we will continue to review quadratic, using both the formula and the factorisation methods. Let us begin with the solution to the homework given last week.

  • Solve 2x2 - 6x - 1 = 0

Using the formula x = ( (-b (+ or -) square root of b2 - 4ac)/2a)

From the equation, a = 2, b = -6 and c = -1

... x = ( (-6 (+ or -) square root of (-6)2 - 4 x 2 x -1)/2 x 2)

... x = 6 (+ or -) square root of (36 + 8)/4)

x = 6 (+ or -) square root of 44/4

... x = 6 (+ or -) 6.63/4

... x = (6 + 6.63)/4 = 12.63/4 = 3.16

And x = (6 - 6.63)/4 = -0.63/4 = -0.16

Answer: x = 3.16 and -0.16

  • Solve 2x2 - 3x - 4 = 2 - 4x

First make the right side equal to zero:

... 2x2 - 3x + 4x - 4 - 2 = 0

... 2x2 + x - 6 = 0 Factorising

(2x - 3)(x + 2) = 0

... 2x - 3 = 0, that is x = 3/2

And x + 2 = 0, that is x = -2.

Answer: x = 3/2 and -2

Let us now proceed to use the COMPLETION OF SQUARES method to reorganize a quadratic expression.

COMPLETION OF SQUARES

The quadratic expression is changed to a format which enables you to determine the following:

(1) The axis of symmetry
(2) The maximum or minimum value

Given the quadratic expression x2 + bx + c, the aim is to convert the expression to the form (x + d)2 + k, where d and k are constants. The method requires two steps as follows.

  • You are, therefore, required to CONVERT x2 + bx to a PERFECT SQUARE of the form (x + d)2. This is based on the following equation: (x + d)2 = x2 + 2dx + d2
    Given x2 + 2dx, then d2, the square of half the coefficient of x, must be added to complete the perfect square.
  • When b2 is added to make x2 + bx a perfect square, then b2 is also subtracted to avoid change in value of the expression. It follows, therefore, that x2 + bx + c is converted to x2 + bx + d2 + c - d2.

EXAMPLE

Express x2 + 6x + 3 in the form (x + d)2 + k, where d and k constants.
Convert x2 + 6x + 3 to the form (x2 + 6x) + 3. As shown above 9 is added to x2 + 6x to make it perfect square. When 9 is added then 9 is also subtracted to avoid changinng the value of the expression.

... (x2 + 6x) + 3 = (x2 + 6x) + (6/2)2 + 3 - (6/2)2

= (x2 + 6x + 9) + 3 - 9
= (x + 3)2 - 6

... d = 3 and k = -6

(x + d)2 + k, where d and k are constants. The method requires two steps as follows.

  • You are therefore, required to CONVERT x2 + bx to a PERFECT SQUARE of the form (x + d)2. This is based on the following equation:
    (x + d)2 = x2 + 2dx + d2
    Given x2 + 2dx, then d2, the square of half the coefficient of x, must be added to complete the perfect square.
  • When b2 is added to make x2 + bx a perfect square, then b2 is also subtracted to avoid change in value of the expression, It follows, therefore, that x2 + bx + c is converted to x2 + bx + d2 + c - d2

EXAMPLE

Express x2 + 6x + 3 in the form (x + d)2 + k, where d and k are constants.
Convert x2 + 6x + 3 to the form (x2 + 6x) + 3. As shown above 9 is added to x2 + 6x to make it perfect square. When 9 is added then 9 is also subtracted to avoid changing the value of the expression.

... (x2 + 6x) + 3 = (x2 + 6x) + (6/2)2 + 3/2 - (6/2)2

= (x2 + 6x + 9) + 3 - 9

= (x + 3)2 - 6

... d = 3 and k = -6

EXAMPLE

Express 2x2 - 3x + 1 in the form a(x + h)2 + k where a, h and k are real numbers.
2x2 - 3x + 1 = 2(x2 - (3/3)x) + 1

Complete the squares inside the bracket.

... 2(x2 + (3/2)x + (3/4)2 + 1

NB (3/4)2 is added within the bracket so the real value is 2 (3/4)22

= 2 (x2 - (3/2)x + 9/16) - 9/8 + 1

= 2 (x - 3/4)2 - 1/8

You may expand to show that the value of the expression remain the same.

... a = 2, h = -3/4 and k = -17/8

We will complete the lesson with another example.

EXAMPLE

Express f(x) = 2x2 - 4x - 13 in the form f(x) = a (x + h)2 + k

= 2x2 - 4x - 13 = (2x2 - 4x) - 13

= 2 (x2 - 2x) - 13

Completing the square

... = 2(x2 - 2x + 1) - 2 x 1 - 13
= 2(x - 1)2 - 15
... f(x) = 2(x - 1)2 - 15

For Homework please attempt the following:

1. Solve the equation x2 + 4x - 3
2. Solve the equation 2x2 + 5x = 9
3. Solve the equation 4x2 + 9x + 10 = 4 - 2x
4. Express 2x2 + 4x - 7 in the form a(x + b)2 + c
5. Express 3x2 - 2x + 1 in the form a(x + b)2 + c

Clement Radcliffe is principal of Glenmuir High School. Send questions and comments to kerry-ann.hepburn@gleanerjm.com

 
 
Youthlink Club
If You can write about anything at all, like aliens or teachers, parents or friends, love or war. But secretly we are hoping to also get the buzz on what's hot, and what's not; exam blues and school news; your views and other dos. Join as part of your school's journalism club or as an individual member.
Click here for more Info


 

FeedBack   |   Join Youthlink Club   |   Youthlink Message Board   |   Write To Dear Counsellor

Other Links
Go-Local Jamaica
   |   Da Flex    |   Jamaica Gleaner   |   Jamaica Star   |   Discover Jamaica   |   Go-Jamaica.com

Newspapers in Education | Business Directory