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Completion
of Squares
Clement Radcliffe,Contributor
In
this week's lesson we will continue
to review quadratic, using both the
formula and the factorisation methods.
Let us begin with the solution to
the homework given last week.
Using
the formula x = ( (-b (+ or -) square
root of b2 - 4ac)/2a)
From
the equation, a = 2, b = -6 and c
= -1
...
x = ( (-6 (+ or -) square root of
(-6)2 - 4 x 2 x -1)/2 x
2)
...
x = 6 (+ or -) square root of (36
+ 8)/4)
x
= 6 (+ or -) square root of 44/4
...
x = 6 (+ or -) 6.63/4
...
x = (6 + 6.63)/4 = 12.63/4 = 3.16
And
x = (6 - 6.63)/4 = -0.63/4 = -0.16
Answer:
x = 3.16 and -0.16
- Solve
2x2 - 3x - 4 = 2 - 4x
First
make the right side equal to zero:
...
2x2 - 3x + 4x - 4 - 2 =
0
...
2x2 + x - 6 = 0 Factorising
(2x
- 3)(x + 2) = 0
...
2x - 3 = 0, that is x = 3/2
And
x + 2 = 0, that is x = -2.
Answer:
x = 3/2 and -2
Let
us now proceed to use the COMPLETION
OF SQUARES method to reorganize
a quadratic expression.
COMPLETION
OF SQUARES
The
quadratic expression is changed to
a format which enables you to determine
the following:
(1)
The axis of symmetry
(2)
The maximum or minimum value
Given
the quadratic expression x2
+ bx + c, the aim is to convert the
expression to the form (x + d)2
+ k, where d and k are
constants. The method requires two
steps as follows.
- You
are, therefore, required to CONVERT
x2 + bx to a PERFECT
SQUARE of the form (x + d)2.
This is based on the following equation:
(x + d)2 = x2
+ 2dx + d2
Given
x2 + 2dx, then d2,
the square of half the coefficient
of x, must be added to complete
the perfect square.
- When
b2 is added to make x2
+ bx a perfect square, then b2
is also subtracted to avoid change
in value of the expression. It follows,
therefore, that x2 +
bx + c is converted to x2
+ bx + d2 + c - d2.
EXAMPLE
Express
x2 + 6x + 3 in the form
(x + d)2 + k, where d and
k constants.
Convert x2 + 6x + 3 to
the form (x2 + 6x) + 3.
As shown above 9 is added to x2
+ 6x to make it perfect square. When
9 is added then 9 is also subtracted
to avoid changinng the value of the
expression.
...
(x2 + 6x) + 3 = (x2
+ 6x) + (6/2)2 + 3 - (6/2)2
=
(x2 + 6x + 9) + 3 - 9
= (x + 3)2 - 6
...
d = 3 and k = -6
(x
+ d)2 + k, where d
and k are constants. The method
requires two steps as follows.
- You
are therefore, required to CONVERT
x2 + bx to a PERFECT
SQUARE of the form (x + d)2.
This is based on the following equation:
(x + d)2 = x2
+ 2dx + d2
Given x2 + 2dx, then
d2, the square of half
the coefficient of x, must be added
to complete the perfect square.
- When
b2 is added to make x2
+ bx a perfect square, then b2
is also subtracted to avoid change
in value of the expression, It follows,
therefore, that x2 +
bx + c is converted to x2
+ bx + d2 + c - d2
EXAMPLE
Express
x2 + 6x + 3 in the form
(x + d)2 + k, where d and
k are constants.
Convert x2 + 6x + 3 to
the form (x2 + 6x) + 3.
As shown above 9 is added to x2
+ 6x to make it perfect square. When
9 is added then 9 is also subtracted
to avoid changing the value of the
expression.
...
(x2 + 6x) + 3 = (x2
+ 6x) + (6/2)2 + 3/2 -
(6/2)2
=
(x2 + 6x + 9) + 3 - 9
=
(x + 3)2 - 6
...
d = 3 and k = -6
EXAMPLE
Express
2x2 - 3x + 1 in the form
a(x + h)2 + k where a, h and k are
real numbers.
2x2 - 3x + 1 = 2(x2
- (3/3)x) + 1
Complete
the squares inside the bracket.
...
2(x2 + (3/2)x + (3/4)2
+ 1
NB
(3/4)2 is added within
the bracket so the real value is 2
(3/4)22
=
2 (x2 - (3/2)x + 9/16)
- 9/8 + 1
=
2 (x - 3/4)2 - 1/8
You
may expand to show that the value
of the expression remain the same.
...
a = 2, h = -3/4 and k = -17/8
We
will complete the lesson with another
example.
EXAMPLE
Express
f(x) = 2x2 - 4x - 13 in
the form f(x) = a (x + h)2
+ k
=
2x2 - 4x - 13 = (2x2
- 4x) - 13
=
2 (x2 - 2x) - 13
Completing
the square
...
= 2(x2 - 2x + 1) - 2 x
1 - 13
= 2(x - 1)2 - 15
... f(x) = 2(x - 1)2 -
15
For
Homework please attempt the following:
1.
Solve the equation x2 +
4x - 3
2. Solve the equation 2x2
+ 5x = 9
3. Solve the equation 4x2
+ 9x + 10 = 4 - 2x
4. Express 2x2 + 4x - 7
in the form a(x + b)2 +
c
5. Express 3x2 - 2x + 1
in the form a(x + b)2 +
c
Clement
Radcliffe is principal of Glenmuir
High School. Send questions and comments
to kerry-ann.hepburn@gleanerjm.com
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