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CSEC>> Mathematics

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Review
Clement Radcliffe,Contributor

This week we will continue the review of algebra with the solution to last week's homework.

Points to Note

The following methods are used to solve quadratic equations:

Factorisation

Formula method

It should be noted that the formula method is used when the quadratic expression cannot be factorised. Now let us review the homework.

Homework

1. Solve the equation x2 + 4x - 3 = 0

Using the formula, x = ( -b ± vb2 - 4ac )/2a

From the equation, a = 1, b = 4 and c = - 3

Substituting, x = ( -4 ± v42 - 4x1x-3 )/2x1

Simplifying, x = ( - 4 ± v16 + 12 )/2 = ( - 4 ± v28 )/2

x = ( - 4 ± 5.3 )/2

x = ( - 4 + 5.3 )/2

x = 1.3/2 = 0.65

x = (- 4 - 5.3 )/2 = -9.3/2 = -4.65

Answer x = 0.65 or -4.65

2. Solve: 4x2 + 9x +10 = 4 - 2x

Since 4x2 + 9x + 10 = 4 - 2x

4x2 + 9x + 2x + 10 - 4 = 0

4x2 + 11x + 6 = 0

Factorizing: ( 4x + 3) (x + 2) = 0

4x + 3 = 0; 4x = -3 x = -3/4

x + 2 = 0 x = - 2

Answer x = - 3/4 , or -2

3. Express 2x2 + 4x -7 in the form a(x + b)2 + c

2x2 + 4x -7 is expressed as (2x2 + 4x) - 7

(2x2 + 4x) - 7 = 2(x2 + 2x) - 7

Completing the square within the bracket

2(x2 + 2x) - 7 = 2(x2 + 2x + 1) - 2 - 7

= 2(x + 1)2 - 9

a = 2, b = 1 and c = -9

4. Express 3x2 - 2x + 1 in the Form a(x + b)2 + c

(3x2 - 2x) + 1 = 3(x2 - 2/3 x) + 1

To complete the square within the bracket we add the square of half the coefficient of x

3(x2 - 2/3 x) + 1 = 3(x2 - ? x + ( 1/3 )2) - 3x(1/3)2 + 1

= 3 (x - 1/3)2 - 3/9 + 1

= 3 (x - 1/3)2 + 2/3

a = 3, b = -1/3, c = 2/3

Continuing, we will review the application of completion of squares.

These are:

1. Equation of the axis of symmetry.

2. Maximum or minimum value of the expression.

Example:

Given the expression (a) 2x2 + 4x - 7

(b) 3x2 - 2x + 1 find the following

a) The equation of the axis of symmetry

b) The minimum value of the expression

Since 2x2 + 4x - 7 may be expressed in the form

y = 2(x + 1)2 - 9, then the equation of the axis of symmetry is given

as x + 1 = 0, x = - 1

The minimum value of y = -9

Do you know why?

2(x + 1)2 is positive for all real values of x. It follows that for all

values of x, the values of the expression are all greater than - 9.

Since 3x2 - 2x + 1 may be expressed in the form y = 3 (x - 1/3)2 + 2/3

Then the equation of the axis of symmetry is x - 1/3 = 0; x = 1/3

The minimum value of y = 2/3

Since y = 3( x - 1/3)2 + 2/3

N.B. When x = 1/3, then 3 (x - 1/3)2 = 0

y = 2/3

For all other values of x, 3 (x - 1/3)2 is a positive number
y is greater than 2/3
2/3 is the minimum value

We will continue the review of algebra by returning to the solution of simultaneous equations. This week I will deal specifically with those cases in which one equation is linear and one quadratic.

Simultaneous equations - One linear and one quadratic.
The substitution method is used.

Example:

Solve the following equations:

y = x2 + 3x - 7 . . . (1)
y + x = 5 . . . ........(2)

The substitution method is used as follows:

From equation (2), y = 5 - x

Substituting y = 5 - x in equation (1),

5 - x = x2 + 3x - 7

x2 + 3x + x - 7- 5 = 0.

x2 + 4x - 12 = 0

Using the factorisation method:

(x + 6)(x - 2) = 0

x = 2 and - 6. Substituting in equation (2),

y = 3 and 11. Answers: x = 2, y = 3 and x = - 6, y = 11.

Kindly note the following:

(a) There are two sets of values because of the quadratic equation.

(b) The basic principles of algebra should be well known, as they are required.

If your solutions have large values, for example 136, it is likely that an error has been made. It is therefore recommended that you check your working.

Here is another example.

Example

Determine two numbers whose sum is 9 and whose product is 20, by solving a quadratic equation.

Let the numbers be x and y.

x + y = 9 . . . (1)
x x y = 20 ... (2)

From equation (1),

x = 9 - y . . . (3)

Substituting equation (3) in equation (2),

(9 - y) x y = 20

9y - y2 = 20

y2 - 9y + 20 = 0 Factorising

(y - 5)(y - 4) = 0

y - 5 = 0. y = 5

OR

y - 4 = 0 y = 4.

Substituting into equation (1)

When y = 5

5 + x = 9 x = 4

When y = 4 4 + x = 9 x = 5

Answer

y = 5 and x = 4

OR

y = 4 and x = 5.

Please attempt to solve the following on your own:

x22 + 9y2 = 37
x - 2y = -3

y - x =1
y = x2 - 3x + 4

Enjoy the rest of the week.

Clement Radcliffe is an independent contributor. Send questions and comments to kerry-ann.hepburn@gleanerjm.com

 
 


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